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  4. How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g HCl? [Given: atomic mass of Pb = 208 u]

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Q. How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g HCl?

[Given: atomic mass of Pb = 208 u]

NTA AbhyasNTA Abhyas 2020Some Basic Concepts of Chemistry

Solution:

$\underset{\underset{\underset{0.029 \text{mol}}{\frac{6.5}{224} \text{mol}}}{}}{\text{PbO}} + \underset{\underset{\underset{0.087 \text{mol}}{\frac{3.2}{36.5} \text{mol}}}{}}{2 \text{HCl}} \rightarrow \underset{}{\text{PbCl}_{2}} + \text{H}_{2} \text{O}$

Formation of moles of lead (II) chloride depends upon the number of moles of PbO which acts as a limiting factor here. So, number of moles of $PbCl_{2}$ formed will be equal to the number of moles of PbO i.e. 0.029.