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  4. How many moles of electrons weigh one kilogram? (mass of electron =9.108 × 10-31 kg, Avogadro number .=6.023 × 1023)

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Q. How many moles of electrons weigh one kilogram? (mass of electron $=9.108 \times 10^{-31} kg$, Avogadro number $\left.=6.023 \times 10^{23}\right)$

Structure of Atom

Solution:

As mass of one electron $=9.108 \times 10^{-31} kg$
So, $1 kg$ of electrons $=1 / 9.108 \times 10^{-31}$
$=\frac{10^{31}}{9.108 \times 6.022 \times 10^{23}} mol$
$=\frac{10^{31-23}}{9.108 \times 6.022} mol$
$=\frac{10^{8}}{9.108 \times 6.022} mol$