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  4. How many molecules of CO2 are formed when one milligram of 100 % pure CaCO3 is treated with excess hydrochloric acid?

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Q. How many molecules of $CO_2$ are formed when one milligram of $100\%$ pure $CaCO_3$ is treated with excess hydrochloric acid?

KEAMKEAM 2013Some Basic Concepts of Chemistry

Solution:

$\underset{100 g}{CaCO_{3}}+2HCl \to CaCl_2+H_2O+\underset{\text{1 mol}}{CO_{2}}$

$=6.022 \times 10^{23}$ molecules

$\because \,100 \,g \, CaCO _{3}$ gives, molecules of $C O _{2}$

$=6.1022 \times 10^{23}$

$\therefore \,1 \times 10^{-3} \,g \,CaCO _{3}$ gives molecules of $CO _{2}$

$=\frac{6.022 \times 10^{23} \times 1 \times 10^{-3}}{100} $

$=6.022 \times 10^{18}$