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Q.
How many millilitres of $0.5\, M \,H_2SO_4$ are needed to dissolve
$0.5 \,g$ of copper (II) carbonate?
IIT JEEIIT JEE 1999Some Basic Concepts of Chemistry
Solution:
The balanced chemical reaction is
$CuCO _{3}+ H _{2} SO _{4} \longrightarrow CuSO _{4}+ H _{2} O + CO _{2} $
millimol of $ CuCO _{3} =\frac{0.5 \times 1000}{123.5}=4.048$
$\because $ Millimol of $ H _{2} SO _{4}$ required $=4.048 $
Millimol $=$ Molarity $ \times $ Volume (in mL)
$\Rightarrow $ Volume $=\frac{4.048}{0.50}=8.096 \,mL$