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  4. How many litres of Cl2 at STP will be liberated by the oxidation of NaCl with 10 g KMnO4 ?

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Q. How many litres of $Cl_{2}$ at STP will be liberated by the oxidation of NaCl with 10 g $KMnO_{4}$ ?

NTA AbhyasNTA Abhyas 2022

Solution:

Meq. of $Cl_{2}=Meq.$ of $KMnO_{4}$
$\frac{w}{71 / 2}\times 1000=\frac{10}{31.6}\times 1000$
So $w_{C l_{2}}=11.23$ g
So $V_{C l_{2}}=\frac{22.4 \times 11.23}{71}=3.54$ litre.