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Q. How many joules of heat are absorbed when $ 70.0 \,g $ of water is completely vaporised at its boiling point ?

UPSEEUPSEE 2009

Solution:

Since the process involves phase change, heat absorbed,

$Q=$ mass $\times$ latent heat of vaporisation

Given, mass $=70.0\, g =0.07 \,kg$

$L_{v}=2260 \,kJ / kg$

$\therefore Q=0.07 \times 2260\, kJ$

$=158.2 \,kJ$

$=158200 \,J .$