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  4. How many grams of water will be electrolysed by 96500 coulomb?

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Q. How many grams of water will be electrolysed by $96500$ coulomb?

Electrochemistry

Solution:

$W=\frac{E \times Q}{96500}$ Given $Q =96500 C$ and $E\left( H _{2} O \right)=9\, g$

$\therefore W=\frac{9 \times 96500}{96500}=9\, g$