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  4. How many grams of NaOH are present in 250 mL of 0.5 M NaOH solution?

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Q. How many grams of $NaOH$ are present in $250\, mL$ of $0.5 \,M\, NaOH$ solution?

Solutions

Solution:

No. of moles of $NaOH$
$= \frac{M \times V}{1000} = \frac{0.5 \times 250}{1000} = 0.125$
Mass of $NaOH = 40 \times 0.125 = 5 \,g$