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  4. How many grams of methyl alcohol should be added to 10 litre tank of water to prevent its freezing at 268 K ? (Kf for water is 1.86 K kg mol-1 )

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Q. How many grams of methyl alcohol should be added to $10$ litre tank of water to prevent its freezing at $268\, K$ ? $\left(K_{f} \, for\, water\, is \,1.86 K\, kg \, mol^{-1} \right)$

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Solution:

$\Delta T_{f} =K_{f} m$
where m = molality
273 - 268= 1.86 x $\frac{w}{M\times V}$
$5=1.86 \times\frac{w}{32\times10}$
$W=\frac{5\times32\times10}{1.86}$
$=860.2 \approx 868.06 g$