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Q.
How many gram of $H_{2}S$ will react with $63.2g$ of $KMnO_{4}$ to produce $K_{2}SO_{4}$ and $MnO_{2}?$ Give answer after rounding off to the nearest integer.
NTA AbhyasNTA Abhyas 2022
Solution:
According to the Question:
The equivalents of $H_{2}S=$ The equivalents of $KMnO_{4}$
So,
$8\times MolesofH_{2}S=3\times Moles\text{of}KMnO_{4}\text{Let}w\text{is required mass of}H_{2}S.$
So,
$\frac{8 \times w}{\left(34\right)}=\frac{3 \times 63 . 2}{\left(158\right)}w=5g.$