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Q. How many gram equivalents of NaOH are required to neutralize 25 $cm^3$ of decinormal HCl solution ?

Equilibrium

Solution:

$1000\,cm^{3}$ of $0.1\,N\,Cl$ neutralizes $0.1\, g$ eq. of $NaOH$
$25\, cm^{3}$ of $0.1\,N\,HCl$ neutralizes $NaOH$
$=\frac{0.1}{1000} \times 25$
$=0.0025\,g$ eq