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Q. How many gm of silver will be displaced from a solution of $AgNO_3$ by $4\, gm$ of magnesium?

AIIMSAIIMS 1995Electrochemistry

Solution:

Given: Weight of magnesium = $4 \,gm$,

We know that $\frac{\text { Weight of silver displaced }(M)}{\text { Weight of magnesium }}$

$=\frac{\text { Equivalent weight of silver }}{\text { Equivalent weight of magnesium }}$

or $\frac{M}{4}=\frac{108}{12}$

or $M=\frac{108 \times 4}{12}=36 \,gm$