Thank you for reporting, we will resolve it shortly
Q.
How many $g$ of $NaOH$ will be needed to prepare $250\, mL$ of $0.1\, M$ solution?
ManipalManipal 2015
Solution:
$M _{ eq }$ of $NaOH =$ Volume $\times$ Molarity $=250 \times 0.1=25$
Let's now find how many g of $NaOH$ will be needed to prepare $250\, mL$ of $0.1\, M$ solution $\frac{w}{40} \times 1000=25$
$w=1\, g.$