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Q. How many $g$ of $NaOH$ will be needed to prepare $250\, mL$ of $0.1\, M$ solution?

ManipalManipal 2015

Solution:

$M _{ eq }$ of $NaOH =$ Volume $\times$ Molarity $=250 \times 0.1=25$
Let's now find how many g of $NaOH$ will be needed to prepare $250\, mL$ of $0.1\, M$ solution $\frac{w}{40} \times 1000=25$
$w=1\, g.$