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  4. How many Faradays are required to reduce 1 mol of Cr 2 O 72- to Cr 3+ in acidic medium?

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Q. How many Faradays are required to reduce $1 $ mol of $Cr _{2} O _{7}^{2-}$ to $Cr ^{3+}$ in acidic medium?

Electrochemistry

Solution:

In acidic medium,

$Cr _{2} O _{7}^{2-}+14 H ^{+}+6 e^{-} \rightarrow 2 Cr ^{3+}+7 H _{2} O$

Thus, $n=6$

Hence, $6 F$ charge is required to reduce $1 \,mol$ of $Cr _{2} O _{7}^{2-}$ to $Cr ^{3+}$ in acidic medium.