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Q.
How many elements would be in the II $^{\text {nd }}$ period of the Periodic Table if the spin quantum numbers could have the value $+\frac{1}{2}, 0,-\frac{1}{2} ?$
Structure of Atom
Solution:
For II $^{nd}$ period
$n=2$ hence,
Hence, total number of elements (total value of spin quantum number) = 12