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Q. How many electrons should $X _{2} H _{4}$ liberate so that in the new compound, X shows oxidation number of $-1 / 2 ?$ [E.N. of $X .>H]$

Redox Reactions

Solution:

Let the number of electrons liberated be $x$ then the total charge on compound will be $x$.
$\therefore 2 \times\left(-\frac{1}{2}\right)+4 \times 1= x$
$x=3$