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  4. How many electrons should be removed from a coin of mas 1.6 g, so that it may float in an electric field of intensity 109 N / C directed upward?

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Q. How many electrons should be removed from a coin of mas $1.6\, g$, so that it may float in an electric field of intensity $10^{9}\, N / C$ directed upward?

Electric Charges and Fields

Solution:

$q E=m g$
$ neE =m g$
Use $n=\frac{m q}{e E}$