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  4. How many electrons in copper atom (29Cu) have (n + l) = 4

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Q. How many electrons in copper atom $(_{29}Cu)$ have $(n + l) = 4$

Structure of Atom

Solution:

$_{29}CU$ is $1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^1$.
The electrons having $(n + l) = 4$ are present in $3p$ and $4s$ shells. Hence total number of such electrons is $7$.