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Q. How many electrons in an atom with atomic number 105 can have $(n + l) = 8$ ?

Structure of Atom

Solution:

Write the configuration of $105$ and find out electrons with $n + l = 8$.
There are $14$ electrons in $5f$-orbitaIs $(5 + 3 = 8)$ and $3$ electrons in $6d$-orbitals $(6+2 = 8 )$ making total $= 17$.