Question

How many degrees of freedom are associated with $2$ grams of $He$ at NTP ?

• A. $3$
• B. $3.01 \times 10^{23}$
• C. $9.03 \times 10^{23}$
• D. $6$

Answer 1

Answer: (C)

Moles of $He =\frac{2}{4}=\frac{1}{2}$
Molecules $=\frac{1}{2} \quad 6.02 \quad 10^{23}=3.01 \times 10^{23}$
As there are 3 degrees of freedom corresponding to 1 molecule of a monatomic gas
Total degrees of freedom $=3 \times 3.01 \times 10^{23}$