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  4. Hot and conc. KMnO4 at 373-383 K reacts with pent-2-ene to form

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Q. Hot and conc. $KMnO_{4}$ at 373-383 K reacts with pent-2-ene to form

NTA AbhyasNTA Abhyas 2020Hydrocarbons

Solution:

Hot and conc. $KMnO_{4}$ at 373-383 K reacts with pent-2-ene to form a mixture of propanoic acid and ethanoic acid.

$CH_{3}CH_{2}CH=CHCH_{3}\overset{K M n O_{4}}{ \rightarrow }\underset{P r o p a n o i c a c i d}{C H_{3} C H_{2} C O O H}+\underset{E t h a n o i c a c i d}{H O O C C H_{3}}$