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  4. Hexafluoroferrate (III) ion is an outer orbital complex. The number of unpaired electrons present in it is

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Q. Hexafluoroferrate (III) ion is an outer orbital complex. The number of unpaired electrons present in it is

Coordination Compounds

Solution:

Hexafluoroferrate (III) ion $\left[ FeF _{6}\right]^{-3}$
Electronic configuration of $Fe :[ Ar ] 4 s ^{2} 3 d ^{6}$
Here $Fe$ shows oxidation state of $+3$.
Thus, its electronic configuration can be given as $[ Ar ] 3 d ^{5}$
Thus, it has $5$ unpaired electrons
The electron pairs donate by $F$ enters into $4 s , 4 p$ and two $4 d$ subshell to form $sp ^{3} d ^{2}$ hybrid orbital.
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