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  4. Henry’s law constant for molality of methane in benzene at 298 K is 4.27 × 105 mm Hg. The mole fraction of methane in benzene at 298 K under 760 mm Hg is

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Q. Henry’s law constant for molality of methane in benzene at $298\, K$ is $4.27 \times 10^5 \,mm \,Hg$. The mole fraction of methane in benzene at $298 \,K$ under $760\, mm \,Hg$ is

Solutions

Solution:

According to Henry’s law, $p = K_Hx$
$x = \frac{p}{K_{H}} = \frac{760}{4.27 \times 10^{5}}$
$= 1.78 \times 10^{-3}$