Question

Henry's law constant for $CO _{2}$ in water is $1.67 \,K$ bar at $25^{\circ} C .$ The quantity of $CO _{2}$ in $1000\, mL$ of soda water when packed under $5$ bar $CO _{2}$ pressure at $25^{\circ} C$ is

• A. 0.084 mol
• B. 0.167 mol
• C. 0.252 mol
• D. 0.336 mol

Answer 1

Answer: (B)

We know that

$p =K_{H} \chi_{i} $

$\Rightarrow \,p=K_{H} \times \frac{n_{1}}{n_{1}+n_{2}} $

Given is p = pressure (5 bar )

$K_{H} $ = Henery's constant $(1.67 \,K $ bar)

$\chi_{1} $ = mole fraction of solute $CO _{2} $

$\chi_{1} =\frac{n_{1}}{n_{1}+n_{2}}$

$ \Rightarrow \, 5=1.67 \times 10^{3} \times \frac{H_{1}}{55.5} $

$H_{1} =\frac{55.5 \times 5}{1.67 \times 10^{3}}=0.167\, mol$