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  4. Heat required to melt 1 g of ice is 80 cal. A man melts 60 g of ice by chewing in one minute. His power is:

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Q. Heat required to melt $1\,g$ of ice is $80\,cal$. A man melts $60\,g$ of ice by chewing in one minute. His power is:

Thermal Properties of Matter

Solution:

= ML = $60\times80$ = $4800cal$ = $4800 \times 4.2J$.
P = $\frac{Q}{T}=\frac{4800\times4.2}{60}=336\,W$