The enthalpy of neutralization of any strong acid with a strong base is always the same, i.e., 57.1 kJ. This is because the strong acids, strong bases and the salts they form, are all completely ionized in dilute aqueous solution.
$ Na^+ = OH^- + H^+ + Cl^- \rightarrow Na^+ + Cl^- + H_2 O$ or $ H^+_{(aq)} + OH^-_{(aq)} \rightarrow H_2O_{(l)} $
i.e.; 1 mole of water is formed from $H^+$ and $OH^-$ ions.