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Q. Heat of neutralisation of HF (a weak acid) with strong base is $ -\text{ }16.4\text{ }kcal. $ Calculate heat of ionisation of HF in water.

Jharkhand CECEJharkhand CECE 2013

Solution:

(i) $ HF+O{{H}^{-}}\xrightarrow{{}}{{H}_{2}}O+{{F}^{-}};\Delta H =-16.4\,kcal $
(ii) $ {{H}^{+}}+O{{H}^{-}}\xrightarrow{{}}{{H}_{2}}O;\Delta H=-13.7\,kcal $
From Eqs. (i)-(ii) gives the required equation (ionisation of HF in water)
$ HF\xrightarrow{{}}{{H}^{+}}+{{F}^{-}};\Delta H =-2.7kcal. $