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Q. Heat energy absorbed by a system in going through a cyclic process shown in figure is :-
Question

NTA AbhyasNTA Abhyas 2020

Solution:

In a cyclic, $\Delta U=0$
From $FLOT,\Delta Q=\Delta U+\Delta W=0+\Delta W=$ Area
of closed curve
$\Rightarrow Q=\pi r^{2}=\pi \left(\frac{20}{2}\right)^{2}kP_{a}\times $ litre
$=100\pi \times 10^{3}\times 10^{- 3}J=100\pi J$