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  4. Haloalkane in the presence of alcoholic KOH undergoes

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Q. Haloalkane in the presence of alcoholic $KOH$ undergoes

AFMCAFMC 2011

Solution:

Haloalkanes on boiling with alcoholic $KOH$ undergoes elimination or dehydrohalogenation.
$\underset{\text{propyl bromide}}{CH _{3} CH _{2} CH _{2} Br +}$ alc. $KOH \longrightarrow \underset{\text{propylene}}{CH _{3} CH = CH _{2}}+ KBr + H _{2} O$