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  4. Half-life period of a first order reaction is 10 min. What percentage of the reaction will be completed in 100 min?

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Q. Half-life period of a first order reaction is $10$ min. What percentage of the reaction will be completed in $100$ min?

Chemical Kinetics

Solution:

$\frac{0.693}{t_{1/2}}$ $=\frac{2.303}{t} \,log$ $\frac{a}{a-x}$
$\frac{0.693}{10}$ $=\frac{2.303}{100}\, log$ $\frac{100}{100-x}$
$\Rightarrow $ $x=99.9\%$