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Q. Hailstone at 0?C falls a from a height of 1 km on an insulating surface converting whole of its kinetic energy into heat. What part of it will melt? $ (g=10m/{{s}^{2}}) $

MGIMS WardhaMGIMS Wardha 2006

Solution:

$ mgh=kmL $ $ k=\frac{gh}{L} $ $ =\frac{10\times 1000}{3.36\times {{10}^{5}}} $ $ =\frac{1}{33} $ ( $ \because $ Latent heat of ice $ =3.36\times {{10}^{5}}\text{ }J/kg $ )