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Q. Haemoglobin contains $0.33 \%$ of iron by weight. The molecular weight of haemoglobin is approximately $67200\, g$. The number of iron atoms (at. weight of $Fe$ is $56$ ) present in one molecule of haemoglobin are

AIPMTAIPMT 1998Some Basic Concepts of Chemistry

Solution:

$\because 0.33 \%$ of iron by weight means $100\, g$ of haemoglobin has $0.33 \,g$ of iron
$100\, g$ of haemoglobin contains iron $=0.33\, g$
$\therefore 67200 \,g$ of haemoglobin contains iron
$=\frac{0.33 \times 67200}{100} g =221.76 g \text { of } Fe$
Number of Fe-atoms $=\frac{221.76}{56}$
$=3.96 \approx 4$