Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $H_2O$ is polar, whereas $BeF_2$ is not because

AIIMSAIIMS 2017Chemical Bonding and Molecular Structure

Solution:

Because of linear shape, dipole moments cancel each other in $BeF _{2}( F \rightleftarrows Be \rightleftarrows F )$ and thus, it is non-polar, whereas $H _{2} O$ is $V$-shaped and hence, it is polar.

Solution Image