Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $H_{2}Se$ has higher boiling point than $H_{2}S$ . This is best explained by

NTA AbhyasNTA Abhyas 2020Chemical Bonding and Molecular Structure

Solution:

Both $H_{2}Se$ and $H_{2}S$ are polar but the former has higher dispersion forces due to its higher molecular weight and hence the higher boiling point.