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Q. $H _{2} O _{2}$ is oxidised by $MnO _{4}{ }^{-}$in acidic medium to form $O _{2}$ and $Mn ^{2+}$. How many gram of $O _{2}$ are produced from $1.5 \times 10^{-3}$ moles of $MnO _{4}^-$ and $1.2$ milligram of $H _{2} O _{2}$ :-

Redox Reactions

Solution:

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$ \frac{1.2 \times 10^{-3}}{34} \times 32$ wt of $O_2$
$ 1.12 \times 10^{-3} gm $ of $O_2$