1. Tardigrade
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  3. Chemistry
  4. H 2+1 / 2 O 2 arrow H 2 O ; Δ H ominus=-68 kcal K + H 2 O + aq arrow KOH ( aq )+1 / 2 H 2 ; Δ H ominus=-48 kcal KOH + aq arrow KOH ( aq ) ; Δ H ominus=-14 kcal From the above data, the standard heat of formation of KOH in kcal is

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Q. $H _2+1 / 2 O _2 \rightarrow H _2 O ; \Delta H^{\ominus}=-68\, kcal$
$K + H _2 O + aq \rightarrow KOH ( aq )+1 / 2 H _2 ; \Delta H^{\ominus}=-48\, kcal$
$KOH + aq \rightarrow KOH ( aq ) ; \Delta H^{\ominus}=-14 \,kcal$
From the above data, the standard heat of formation of $KOH$ in kcal is

Thermodynamics

Solution:

Correct answer is (b) $-68-48+14$