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  4. Glucose is added to 1 litre water to such an extent that (Δ T f / H f ) becomes equal to (1/1000), the weight of glucose added is:

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Q. Glucose is added to 1 litre water to such an extent that $\frac{\Delta T _{ f }}{ H _{ f }}$ becomes equal to $\frac{1}{1000}$, the weight of glucose added is:

NEETNEET 2022

Solution:

$\Delta T_f=K_f \times$ molality $=K_f \times \frac{w \times 1000}{m \times W}$
$\therefore \frac{\Delta T_f}{K_f}=\frac{w \times 1000}{m \times W}$
or $\frac{1}{1000}=\frac{w \times 1000}{180 \times 1000} \therefore w=0.18 g$