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Chemistry
Glucose gives silver mirror with ammoniacal silver nitrate because it has
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Q. Glucose gives silver mirror with ammoniacal silver nitrate because it has
MHT CET
MHT CET 2007
Biomolecules
A
aldehyde group
70%
B
ester group
7%
C
ketone group
10%
D
alcoholic silver nitrate
13%
Solution:
Glucose gives silver mirror with ammoniacal silver nitrate due to the presence of -CHO group (aldehyde group) in the structure of glucose.
$CH_2 OH(CHOH)_4 CHO + Ag_2 O \longrightarrow $
$\underset {\text{gluconic acid}}{CH_2 OH(CHOH)_4} - COOH + \underset {\text{silver mirror}}{2Ag \downarrow} $