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Q. Given: width of aperture $d=3 \,mm$ and $\lambda=500 \,nm$. For what distance ray optics is a good approximation?

Wave Optics

Solution:

$D_{F} =\frac{d^{2}}{\lambda} $
$ D_{F} =\frac{\left(3 \times 10^{-3}\right)\left(3 \times 10^{-3}\right)}{500 \times 10^{-9}} m $
$=\frac{90}{5} m =18 \,m $