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Q. Given the value of Rydberg constant is $10^7 \, m^{-1}$, the wave number of the last line of the Balmer series in hydrogen spectrum will be :

NEETNEET 2016Atoms

Solution:

$\frac{1}{\lambda } = RZ^{2} \left(\frac{1}{n_{2}^{2}} - \frac{1}{n_{1}^{2}}\right) = 10^{7} \times1^{2} \left(\frac{1}{2^{2}} - \frac{1}{ \infty^{2}}\right)$
$ \Rightarrow $ wave number $= \frac{1}{\lambda } = 0.25 \times10^{7} m^{-1} $