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Q. Given that the molecular mass of $KOH$ is $56,$ the weight required to prepare $500 \,mL$ of $N / 20$ solution is

Solutions

Solution:

Normality $=\frac{\text { No. of gram equivalents of solute }}{\text { Volume in litres }}$

$\therefore \frac{1}{20}=\frac{w}{56 \times 500} \times 1000$

$ \Rightarrow w=1.40\, g$