Question

Given that the molecular mass of $KOH$ is $56,$ the weight required to prepare $500 \,mL$ of $N / 20$ solution is

• A. 5.60 g
• B. 0.56 g
• C. 0.28 g
• D. 1.40 g

Answer 1

Answer: (D)

Normality $=\frac{\text { No. of gram equivalents of solute }}{\text { Volume in litres }}$

$\therefore \frac{1}{20}=\frac{w}{56 \times 500} \times 1000$

$\Rightarrow w=1.40\, g$