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Q. Given that the abundant of isotope ${}_{54}Fe$, ${}_{56}Fe$ and ${}_{57}Fe$ are $5\%$, $90\%$ and $5\%$ respectively, the atomic mass of $Fe$ is :

IIT JEEIIT JEE 2009Some Basic Concepts of Chemistry

Solution:

From the given relative abundance, the average weight of $Fe$ can be calculated as
$ A= \frac{ 54 \times 5 +56 \times 90 + 57 \times 5}{100} = 55.95$