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Chemistry
Given that dE=TdS-PdV and H=E+PV . Which one of the following relations is true?
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Q. Given that $ dE=TdS-PdV $ and $ H=E+PV $ . Which one of the following relations is true?
KEAM
KEAM 2009
Thermodynamics
A
$ dH=TdS+VdP $
32%
B
$ dH=SdT+VdP $
15%
C
$ dH=-SdT+VdP $
18%
D
$ dH=dE+PdV $
35%
E
$ dH=dE-TdS $
35%
Solution:
Given, $ dE=TdS-pdV $ ...(i)
$ H=E+pV $ ...(ii) Differentiating Eq. (ii),
$ dH=dE+pdV+vdp $ ...(iii)
From Eq. (i) and (iii),
we get $ dH=TdS+vdp $