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Q. Given that a photon of light of wavelength $10,000\, \mathring{A}$ has an energy equal to $1.23\, eV$. When light of wavelength $5000\, \mathring{A}$ and intensity $I_{0}$ falls on a photoelectric cell, the saturation current is $0.40 \times 10^{-6} A$ and the stopping potential is $1.36\, V$; then the work function is

Dual Nature of Radiation and Matter

Solution:

Since $E \propto \frac{1}{\lambda}$, so energy corresponding to $5000\,\mathring{A}$ is
$E=2.46\, eV$
Now, $h v-W=e V_{s}$
or $2.46\, eV -W=1.36\, eV$
$W=(2.46-1.36) eV =1.1\, eV$