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Chemistry
Given R = 8.314 JK-1 mol-1 , the work done during combustion of 0.090 kg of ethane (molar mass = 30) at 300 K is
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Q. Given $R = 8.314 JK^{-1} mol^{-1}$ , the work done during combustion of $0.090\, kg$ of ethane (molar mass =$ 30$) at $300\, K$ is
MHT CET
MHT CET 2015
A
$-18.7 \, kJ$
B
$18.7\, kJ$
C
$6.234 \,kJ$
D
$- 6.234\, kJ$
Solution:
Since, combustion takes place at constant pressure, hence
$\Delta H=3 W$
$\Delta H =n C_{p} d T$
$\Rightarrow 3 W =\frac{0.090}{30} \times \frac{5}{2} \times 8.314 \times 300$
$=18.7 kJ$