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Q. Given $R = 8.314 JK^{-1} mol^{-1}$ , the work done during combustion of $0.090\, kg$ of ethane (molar mass =$ 30$) at $300\, K$ is

MHT CETMHT CET 2015

Solution:

Since, combustion takes place at constant pressure, hence

$\Delta H=3 W$

$\Delta H =n C_{p} d T$

$\Rightarrow 3 W =\frac{0.090}{30} \times \frac{5}{2} \times 8.314 \times 300$

$=18.7 kJ$