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Q.
Given: Potential difference, $V= \left(8 \pm 0.5\right)V$ and current
$I=\left(2\pm 0.2\right)A$ The value of resistance $R$ in $\Omega$ is
Physical World, Units and Measurements
Solution:
We know that $R=V/I= 8/2 = 4\, \Omega$
Percentage error in $v$ is $\frac{0.5}{8}\times100=6.25$
Percentage error in $I$ is $\frac{0.2}{2}\times100=10$
Now, add up percentage errors and get the answer.