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Q. Given: Force $=\frac{\alpha}{\text { density }+\beta^{3}}$ What are the dimensions of $\alpha, \beta$ ?

Physical World, Units and Measurements

Solution:

$\beta^{3}=$ density $=M^{1} L^{-3}$
$\beta=M^{1 / 2} L^{-1}$
Also; $\alpha=$ force $\times$ density
$=ML T^{-2} \times M^{1} L^{-3}$
$= MLT ^{-2} \times M ^{1} L ^{-3}=\left[ M ^{2} L ^{-2} T ^{-2}\right]$