1. Tardigrade
  2. Question
  3. Chemistry
  4. Given below are the standard electrode potentials of few half-cells. The correct order of these metals in increasing reducing power will be K+/K=-2.93 V, Ag+/Ag=0.80 V, Mg2+/Mg=-2.37 V, Cr3+/Cr=-0.74 V.

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Q. Given below are the standard electrode potentials of few half-cells. The correct order of these metals in increasing reducing power will be
$K^{+}/K=-2.93\,V$, $Ag^{+}/Ag=0.80\,V$,
$Mg^{2+}/Mg=-2.37\,V$, $Cr^{3+}/Cr=-0.74\,V$.

Electrochemistry

Solution:

Higher the oxidation potential, more easily it is oxidised and hence greater is the reducing power. Hence, increasing order of reducing power is
$Ag < Cr < Mg < K$