1. Tardigrade
  2. Question
  3. Chemistry
  4. Given (A) n=5, mℓ =+1 (B) n=2, ℓ=1, mℓ =1, ms =-1/2 The maximum number of electron(s) in an atom that can have the quantum numbers as given in (A) and (B) are respectively:

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Q. Given
(A) $n=5, m_{\ell} =+1$
(B) $n=2, \ell=1, m_{\ell} =1, m_{s} =-1/2$
The maximum number of electron(s) in an atom that can have the quantum numbers as given in (A) and (B) are respectively:

JEE MainJEE Main 2013Structure of Atom

Solution:

(i) n = 5 means 1= 0,1,2,3,4 sincem = + 1 hence total no. of electrons will be =0 (from s) + 2 (fromp) + 2 (fromd) + 2 (from f) + 2 (from g) = 0 + 2 + 2 + 2 + 2 = 8 (ii) n=2, l=1, $m_{t}=1, m_{s} =$ 1/2 represent
2p orbital with one electron