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Chemistry
Gd (64) gives an oxidation state of only +3 because:
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Q. $Gd (64)$ gives an oxidation state of only $+3$ because:
The d-and f-Block Elements
A
It contains 3 unpaired electrons
2%
B
In +3 oxidation state it has unstable configuration
15%
C
In +3 oxidation state it has stable configuration
83%
D
There are 3 electrons present in 4 f in +3 oxidation state
0%
Solution:
In $+3$ oxidation state its configuration is $4 f ^{7}, 5 d ^{0}, 6 s ^{0}$ which is stable as per the rule of extra stability.